2x^2-16x-384=0

Solution for 2x^2-16x-384=0 equation:

2x^2-16x-384=0

a = 2; b = -16; c = -384;
Δ = b2-4ac
Δ = -162-4·2·(-384)
Δ = 3328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3328}=\sqrt{256*13}=\sqrt{256}*\sqrt{13}=16\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16\sqrt{13}}{2*2}=\frac{16-16\sqrt{13}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16\sqrt{13}}{2*2}=\frac{16+16\sqrt{13}}{4}
$